ISTQB-CTAL-TA Exam Dumps : ISTQB Certified Tester Advanced Level - Test Analyst (CTAL-TACore)v3.1.2

Comprehensive and Detailed In-Depth Explanation:

To determine the answer, we first calculate the total score for each player:

Player 1:25×2=5025 \times 2 = 5025×2=50 (Silver)

Player 2:20×3=6020 \times 3 = 6020×3=60 (Silver)

Player 3:30×1=3030 \times 1 = 3030×1=30 (Blue)

The output equivalence partitions based on the trophy levels are:

Blue:Total score ≤ 40

Silver:Total score > 40 and ≤ 70

Gold:Total score > 70 and ≤ 80

Diamond:Total score > 80 and ≤ 90

Platinum:Total score > 90

From the given test cases, the following partitions have been exercised:

Blue (Player 3)

Silver (Player 1 and Player 2)

Out of the 5 possible output partitions (Blue, Silver, Gold, Diamond, Platinum), only2 partitions (Blue and Silver)have been exercised. Therefore, the percentage of partitions covered is:

A number and a percentage sign AI-generated content may be incorrect.

Hence, the correct answer isB (40%).

Comprehensive and Detailed in Depth Explanation:

Boundary Value Analysis (BVA)focuses on values at the edges of equivalence partitions, including just inside and just outside the boundary.

Therevised boundariesare:

£500 and £749for the new 5.5% fee band

£750 and £999for the 4.5% fee band

Testing bothvalid and invalid boundariesis essential to ensure accurate fee calculations.

The correct test cases are:

£499 (just below the lower boundary)

£500 (at the lower boundary)

£749 (at the upper boundary of the first band)

£750 (at the lower boundary of the second band)

£999 (at the upper boundary of the second band)

£1000 (just above the upper boundary)

Therefore, the correct answer isD (499, 500, 749, 750, 999, 1000).

Comprehensive and Detailed in Depth Explanation:

The project has multipledrop-down fields with many values, resulting in numerous combinations.

Pairwise testingis ideal for testing combinations efficiently.

Since the project usesSCRUM methodology, it requiresexploratory testingto accommodate changes and rapid feedback during sprints.

Use case testing (Option A)is not suitable since the focus is on combinations rather than functional sequences.

Decision table testing (Option B)would be less efficient due to the large number of combinations.

Classification Tree (Option C)is more suitable for class-based testing, not pairwise combinations.

Thus, the correct answer isD (Pairwise and exploratory testing).