HPE3-U01 Exam Dumps : Aruba Certified Network Technician Exam (ACNT)

The PCs are not able to successfully establish bidirectional communication because they are on different subnets and their default gateways are not configured correctly. The default gateway is the IP address of the router interface that connects to the same subnet as the PC. The default gateway allows the PC to send packets to destinations outside its own subnet. In this case, PC-1 and PC-2 are on the 172.16.30.0/24 and 172.16.31.0/24 subnets respectively, and the router interfaces are 172.16.30.254 and 172.16.31.254 respectively. Therefore, the correct default gateway for PC-1 is 172.16.30.254 and the correct default gateway for PC-2 is 172.16.31.254. Changing PC-2’s default gateway to 172.16.31.254 will enable the communication between PC-1 and PC-212 References:

• Aruba Certified Network Technician (ACNT) - HPE Certification and Learning
• Aruba Certified Network Technician (ACNT) - Aruba Networks.

Before routers forward unicast packets, they compare the destination address of the IP header with the unicast routing table entries. This is because routers use the destination IP address to determine the next hop or outgoing interface for the packet. Routers do not care about the source address of the IP header or the Ethernet header, as they are not relevant for forwarding decisions. The inbound port the packet is received in is also not important, as routers use the routing table to make forwarding decisions, not the interface information. Therefore, the correct answer is C. References

Given the IP segment 172.16.0.0 255.255.255.0, we can calculate the number of IP addresses that can be assigned to host and network devices using the following formula:

Number of IP addresses=232−n−2

wherenis the number of bits in the network prefix, which is also the number of ones in the subnet mask. In this case, the subnet mask is 255.255.255.0, which in binary is 11111111.11111111.11111111.00000000. Therefore,n=24. Plugging this into the formula, we get:

Number of IP addresses=232−24−2=28−2=256−2=254

However, this number includes the network address (172.16.0.0) and the broadcast address (172.16.0.255), which cannot be assigned to host and network devices. Therefore, we need to subtract 2 more from the result, which gives us:

Number of IP addresses=254−2=252

This means that there are 252 IP addresses that can be assigned to host and network devices in the IP segment 172.16.0.0 255.255.255.0. The answer option that is closest to this number is A, 126.

References:

1: IP Subnet Calculator2: IP Subnetting - The Basic Concepts - NetworkLessons.com3: Subnetting - Wikipedia