HPE3-U01 Exam Dumps : Aruba Certified Network Technician Exam (ACNT)

ARP is a protocol that maps an IP address to a MAC address, which is the physical address of a device on a network. ARP is necessary because the software address (IP address) of the host or computer connected to the network needs to be translated to a hardware address (MAC address). Without ARP, a host would not be able to figure out the hardware address of another host. ARP works by sending a broadcast message to all devices on the network, asking for the MAC address of the device that has a specific IP address. The device that has that IP address replies with its MAC address, and the sender stores this information in its ARP cache for future use. The sender then uses the MAC address as the destination address of the Layer 2 header that encapsulates the IP packet. The Layer 2 header is also known as the data link layer header, which is responsible for delivering the packet to the correct device on the same network. The Layer 3 header is also known as the network layer header, which is responsible for routing the packet to the correct network. Therefore, the correct answer is C, because ARP is used to discover the destination address of the Layer 2 header that encapsulates IP packets1234 References: What Is Address Resolution Protocol (ARP)? - Fortinet, Address Resolution Protocol - Wikipedia, ARP (Address Resolution Protocol) explained - Study-CCNA, Aruba Certified Network Technician Exam HPE3-U01 Actual Questions

 The TCP three-way handshake is a process that is used in a TCP/IP network to create a connection between a client and a server. It involves the exchange of three packets: SYN, SYN-ACK, and ACK. The goal of the TCP three-way handshake is to establish a reliable, flow-controlled connection between the two endpoints. This means that the connection is able to ensure that the data is transmitted without errors, losses, or duplications, and that the data is sent at a rate that both sides can handle.

The TCP three-way handshake works as follows:

• The client initiates the connection by sending a SYN packet to the server. The SYN packet contains a random sequence number that indicates the starting point of the data that the client will send.
• The server responds to the client by sending a SYN-ACK packet. The SYN-ACK packet contains the server’s own sequence number and an acknowledgment number that is equal to the client’s sequence number plus one. This indicates that the server has received the client’s SYN packet and is ready to receive data from the client.
• The client completes the handshake by sending an ACK packet to the server. The ACK packet contains an acknowledgment number that is equal to the server’s sequence number plus one. This indicates that the client has received the server’s SYN-ACK packet and is ready to send data to the server.

After the TCP three-way handshake is completed, the connection is established and the data transfer can begin.

References: The answer can be verified by using the following resources:

• TCP 3-Way Handshake Process - GeeksforGeeks
• TCP 3-Way Handshake (SYN, SYN-ACK,ACK) - Guru99
• Akamai Blog | What is a TCP Three-Way Handshake?
• What is a Three-Way Handshake? - Definition from Techopedia
• What is TCP 3-Way Handshake, Benefits, and Drawbacks? - Networking Signal

The subnet mask 255.255.252.0 is equivalent to the CIDR notation /22, which means that 22 bits are used for the network prefix and 10 bits are used for the host part. To calculate the number of addresses that this subnet mask provides, we can use the formula2n−2, wherenis the number of bits in the host part. In this case,n=10, so the number of addresses is210−2=1024−2=1022. The subtraction of 2 is because the first and the last addresses are reserved for the network identifier and the broadcast address, respectively. Therefore, the subnet mask 255.255.252.0 provides 1022 usable addresses for hosts, plus 2 reserved addresses, for a total of 1024 addresses.References:IP Subnet Calculator,How many host addresses are available on the network … - ITExamAnswers