CTFL_Syll_4.0 Exam Dumps : ISTQB Certified Tester Foundation Level (CTFL) v4.0

This answer is correct because static testing and dynamic testing are both types of testing that can be used to highlight issues associated with non-functional characteristics, such as usability, performance, security, reliability, etc. Static testing is a type of testing that involves the analysis of software work products, such as requirements, design, code, or test cases, without executing them. Dynamic testing is a type of testing that involves the execution of software work products, such as code or test cases, using inputs and verifying outputs. Both static testing anddynamic testing can be applied to different test levels and test types, and can use different test techniques and tools, to evaluate the non-functional characteristics of the software product. References: ISTQB Glossary of Testing Terms v4.0, ISTQB Foundation Level Syllabus v4.0, Section 2.2.1.1, Section 2.2.1.2

Comprehensive and Detailed Explanation From Exact Extract:

This question applies theState Transition Testingtechnique.

Let’s evaluateOption Dstep-by-step:

NORMAL MODE → DEGRADED MODE:✅Valid on“FAILURE DETECTED”

DEGRADED MODE → NORMAL MODE:✅Valid on“ALL FAILURES CLEARED”

NORMAL MODE → DIAGNOSTIC MODE:✅Valid on“SELF DIAGNOSTIC INITIATED”

DIAGNOSTIC MODE → DEGRADED MODE:❌Invalid– there isno defined transitionfrom DIAGNOSTIC MODE directly to DEGRADED MODE.

According to the state diagram, DEGRADED MODE can only be entered:

From NORMAL MODE (on FAILURE DETECTED), or

Not from DIAGNOSTIC MODE at all.

This violates the rule:

“State transition testing uses a model where test cases are designed to execute valid and invalid transitions.”

(ISTQB CTFL Syllabus v4.0, Section 4.2.4 – State Transition Testing, Page 40)

Thus, OptionDcontains aninvalid transition, making it the correct answer.

Equivalence partitioning involves dividing input data into partitions that are treated the same by the system under test. The given specifications create overlapping partitions:

For n<0n < 0n<0, an error message "Value out of range" is issued.

For 0

For 100

However, the range between 0 and 100 is exclusive of 0 and 100, meaning that the partitions overlap and create ambiguity for the boundary values. Thus, the correct statement is that the requirements are not correct because the partitions are overlapping​​.