CTFL_Syll2018 Exam Dumps : ISTQB Certified Tester Foundation Level (Syllabus 2018)

An item or event that could be verified by one or more test cases. A test condition is a general term that refers to anything that can be tested by a test case, such as a requirement, a function, a feature, a use case, a user story, etc. A test condition is derived from the test basis (the source of information for testing) and serves as an input for test design and test case creation. A test condition can be expressed in natural language or in a formal notation. A detailed explanation of test condition can be found in [A Study Guide to the ISTQB® Foundation Level 2018 Syllabus], pages 17-18.

The statement that use case testing is designed to find defects in the process flow is true, because use case testing is a technique that tests the end-to-end user interactions and outcomes based on use cases or scenarios that describe how the software under test should be used . Use case testing can help to find defects in the process flow, such as missing steps, incorrect sequences, or invalid transitions . The other options are not true statements about use case testing. Option A is false, because use case testing is not designed to be used by real users, but rather by professional testers who design and execute test cases based on use cases or scenarios . Option C is false, because use case testing is not designed to find defects in the data flow, but rather in the process flow. Data flow testing is a different technique that tests how data values are defined, used, and modified by the software under test . Option D is false, because use case testing is not always designed by customers or end users, but rather by testers who analyse the requirements or specifications of the software under test to identify use cases or scenarios .

The requirement given in the image specifies an additional fee of $3 that is charged during the weekend, with some exceptions and discounts based on the age of the visitors. To test this requirement, we can use boundary value analysis, which is a specification-based test technique that involves testing the values at or near the boundaries of an equivalence partition. An equivalence partition is a set of values that are expected to be treated in the same way by the system under test. For example, based on the requirement, we can identify the following equivalence partitions for the input age:

• EP1: Age < 0 (invalid)
• EP2: Age = 0 (valid, no charge)
• EP3: 0 < Age < 7 (valid, no charge)
• EP4: Age = 7 (valid, 20% discount)
• EP5: 7 < Age < 13 (valid, 20% discount)
• EP6: Age = 13 (valid, 20% discount)
• EP7: 13 < Age < 65 (valid, full charge)
• EP8: Age = 65 (valid, 50% discount)
• EP9: Age > 65 (valid, 50% discount)

The boundary values for each equivalence partition are the values at or near the edges of the partition. For example, the boundary values for EP3 are 1 and 6. The boundary values for EP4 are 6 and 7. The boundary values for EP5 are 7 and 12. And so on.

To test this requirement using boundary value analysis, we need to select one value from each boundary and test it with different combinations of weekend and weekday. For example, we can select the following values:

• BV1: Age = -1 (from EP1)
• BV2: Age = 0 (from EP2 and EP3)
• BV3: Age = 6 (from EP3 and EP4)
• BV4: Age = 7 (from EP4 and EP5)
• BV5: Age = 12 (from EP5 and EP6)
• BV6: Age = 13 (from EP6 and EP7)
• BV7: Age = 64 (from EP7 and EP8)
• BV8: Age = 65 (from EP8 and EP9)
• BV9: Age = 66 (from EP9)

We can then create test cases using these values and different combinations of weekend and weekday. For example:

• TC1: Age = -1, Weekend = Yes -> Invalid input
• TC2: Age = -1, Weekend = No -> Invalid input
• TC3: Age = 0, Weekend = Yes -> No charge
• TC4: Age = 0, Weekend = No -> No charge
• TC5: Age = 6, Weekend = Yes -> No charge
• TC6: Age = 6, Weekend = No -> No charge
• TC7: Age = 7, Weekend = Yes -> $2.40 ($3 - 20% discount)
• TC8: Age = 7, Weekend = No -> No charge
• TC9: Age = 12, Weekend = Yes -> $2.40 ($3 - 20% discount)
• TC10: Age = 12, Weekend = No -> No charge
• TC11: Age = 13, Weekend = Yes -> $2.40 ($3 - 20% discount)
• TC12: Age = 13, Weekend = No -> No charge
• TC13: Age = 64, Weekend = Yes -> $3
• TC14: Age = 64, Weekend = No -> No charge
• TC15: Age = 65, Weekend = Yes -> $1.50 ($3 - 50% discount)
• TC16: Age = 65, Weekend = No -> No charge
• TC17: Age = 66, Weekend = Yes -> $1.50 ($3 - 50% discount)
• TC18: Age =

66, Weekend = No -> No charge

Therefore, we need a minimum of 18 valid test cases to achieve 100% boundary value coverage based on input age.

$3.01 is not a valid output boundary value because it is not a possible output value based on the requirement. The output values can only be $0, $1.50, $2.40, or $3 depending on the input age and weekend status.

You can find more information about boundary value analysis in [A Study Guide to the ISTQB® Foundation Level 2018 Syllabus], Chapter 4, Section 4.2.