CTFL_Syll2018 Exam Dumps : ISTQB Certified Tester Foundation Level (Syllabus 2018)

It is not allowed as organizations can’t change the test levels as these are chosen on the basis of the SDLC (software development life cycle) model. The V-model is a type of SDLC model that defines four test levels: component testing, integration testing, system testing, and acceptance testing. Each test level corresponds to a development phase in a parallel manner. Integration testing is an essential part of the V-model, as it verifies that the components work together correctly and consistently2 explains this as follows:

The V-model is a graphical representation of a systems development lifecycle. It is used to produce rigorous development lifecycle models and project management models. The V-model falls into three broad categories, the German V-Modell, a general testing model and the US government standard.

The V-model summarizes the main steps to be taken in conjunction with the corresponding deliverables within project execution and delivery. It describes software development activities from requirements specification to maintenance.

The V-Model demonstrates the relationships between each phase of the development life cycle and its associated phase of testing.

A, C, and D are incorrect answers. A implies that integration testing is not an important test level and can be dispensed with, which is not true as integration testing ensures that the system functions as a whole and meets its requirements. C implies that organizations can decide on which test levels to do depending on the context of the system under test, which is not true as test levels are determined by the chosen SDLC model and its objectives. D implies that integration testing is a very important test level and ignoring it means definite poor product quality, which is true but not relevant to why it is not allowed to do away with integration testing in a V-model.

The correct answer is B, as it achieves the highest equivalence partition coverage. Equivalence partitioning is a black-box test technique that divides the input domain into partitions of equivalent data from which test cases can be derived1. In this case, the input domain is the numerical grades, and the partitions are the ranges of grades that correspond to different letter grades. Option B covers all five partitions, as it includes test inputs from each range. Option A covers only four partitions, as it does not include any test input from the range above 89. Option C covers only three partitions, as it does not include any test input from the ranges above 79 and below 60. Option D covers only two partitions, as it does not include any test input from the ranges below 79. References: 1, Section 4.2.3

The requirement given in the image specifies an additional fee of $3 that is charged during the weekend, with some exceptions and discounts based on the age of the visitors. To test this requirement, we can use boundary value analysis, which is a specification-based test technique that involves testing the values at or near the boundaries of an equivalence partition. An equivalence partition is a set of values that are expected to be treated in the same way by the system under test. For example, based on the requirement, we can identify the following equivalence partitions for the input age:

• EP1: Age < 0 (invalid)
• EP2: Age = 0 (valid, no charge)
• EP3: 0 < Age < 7 (valid, no charge)
• EP4: Age = 7 (valid, 20% discount)
• EP5: 7 < Age < 13 (valid, 20% discount)
• EP6: Age = 13 (valid, 20% discount)
• EP7: 13 < Age < 65 (valid, full charge)
• EP8: Age = 65 (valid, 50% discount)
• EP9: Age > 65 (valid, 50% discount)

The boundary values for each equivalence partition are the values at or near the edges of the partition. For example, the boundary values for EP3 are 1 and 6. The boundary values for EP4 are 6 and 7. The boundary values for EP5 are 7 and 12. And so on.

To test this requirement using boundary value analysis, we need to select one value from each boundary and test it with different combinations of weekend and weekday. For example, we can select the following values:

• BV1: Age = -1 (from EP1)
• BV2: Age = 0 (from EP2 and EP3)
• BV3: Age = 6 (from EP3 and EP4)
• BV4: Age = 7 (from EP4 and EP5)
• BV5: Age = 12 (from EP5 and EP6)
• BV6: Age = 13 (from EP6 and EP7)
• BV7: Age = 64 (from EP7 and EP8)
• BV8: Age = 65 (from EP8 and EP9)
• BV9: Age = 66 (from EP9)

We can then create test cases using these values and different combinations of weekend and weekday. For example:

• TC1: Age = -1, Weekend = Yes -> Invalid input
• TC2: Age = -1, Weekend = No -> Invalid input
• TC3: Age = 0, Weekend = Yes -> No charge
• TC4: Age = 0, Weekend = No -> No charge
• TC5: Age = 6, Weekend = Yes -> No charge
• TC6: Age = 6, Weekend = No -> No charge
• TC7: Age = 7, Weekend = Yes -> $2.40 ($3 - 20% discount)
• TC8: Age = 7, Weekend = No -> No charge
• TC9: Age = 12, Weekend = Yes -> $2.40 ($3 - 20% discount)
• TC10: Age = 12, Weekend = No -> No charge
• TC11: Age = 13, Weekend = Yes -> $2.40 ($3 - 20% discount)
• TC12: Age = 13, Weekend = No -> No charge
• TC13: Age = 64, Weekend = Yes -> $3
• TC14: Age = 64, Weekend = No -> No charge
• TC15: Age = 65, Weekend = Yes -> $1.50 ($3 - 50% discount)
• TC16: Age = 65, Weekend = No -> No charge
• TC17: Age = 66, Weekend = Yes -> $1.50 ($3 - 50% discount)
• TC18: Age =

66, Weekend = No -> No charge

Therefore, we need a minimum of 18 valid test cases to achieve 100% boundary value coverage based on input age.

$3.01 is not a valid output boundary value because it is not a possible output value based on the requirement. The output values can only be $0, $1.50, $2.40, or $3 depending on the input age and weekend status.

You can find more information about boundary value analysis in [A Study Guide to the ISTQB® Foundation Level 2018 Syllabus], Chapter 4, Section 4.2.