What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out< int main() { int t[]={8, 10, 5, 1, 4, 6, 2, 7, 9, 3}; int t1[]={1,2,3,4}; deque set sort(d1.begin(), d1.end()); cout<<includes(s1.begin(),s1.end(), t1,t1+4)<<" "< < return 0; } Program outputs:
What will happen when you attempt to compile and run the following code? Choose all that apply.
#include
#include
#include
#include
using namespace std;
class A {
int a;
public:
A(int a) : a(a) {}
int getA() const { return a; } void setA(int a) { this?>a = a; }
bool operator < (const A & b) const { return a }; class F { A val; public: F(A & v):val(v){} bool operator() (A & v) { if (v.getA() == val.getA()) return true; return false; } }; int main() { int t[] = { 10, 5, 9, 6, 2, 4, 7, 8, 3, 1 }; vector v1(t, t + 10); set s1(t, t + 10); A a(6); F f(a); find_if(s1.begin(), s1.end(), f); if (find_if(v1.begin(), v1.end(), f) !=v1.end()) { cout<<"Found!\n"; } else { cout<<"Not found!\n"; } return 0; }