CPP Exam Dumps : C++ Certified Professional Programmer

What happens when you attempt to compile and run the following code?

#include

#include

using namespace std;

int main() {

int t[] = { 1, 1, 2, 2, 3, 3, 4, 4, 5, 5 };

string s[] = { "one", "one", "two", "two", "three","three", "four", "four", "five", "five"};

map m;

for (int i = 0; i < 10; i++) {

m.push_back(pair(t[i], s[i]));

}

for (map::iterator i = m.begin(); i != m.end(); i++) {

cout << i?>first << " ";

}

return 0;

}

What happens when you attempt to compile and run the following code?

#include

#include

#include

#include

using namespace std;

templatestruct Out {

ostream & out;

Out(ostream & o): out(o){}

void operator() (const T & val ) { out<

int main() {

int t[]={8, 10, 5, 1, 4, 6, 2, 7, 9, 3};

int t1[]={1,2,3,4};

deque d1(t, t+10);

set s1(t, t+10);

sort(d1.begin(), d1.end());

cout<<includes(s1.begin(),s1.end(), t1,t1+4)<<" "<

<

return 0;

}

Program outputs:

What will happen when you attempt to compile and run the code below, assuming that you enter the following sequence: 1 2 3 end?

#include

#include

#include

#include

using namespace std;

templatestruct Out {

ostream & out;

Out(ostream & o): out(o){}

void operator() (const T & val ) {out<

int main ()

{

list l;

for( ; !cin.bad() ; )

{

int i;

cin>>i;

l.push_back(i);

}

for_each(l.begin(), l.end(), Out(cout));

return 0;

}

Program will output: