CPP Exam Dumps : C++ Certified Professional Programmer

What happens when you attempt to compile and run the following code?

#include

#include

using namespace std;

template

void print(T start, T end) {

while (start != end) {

std::cout << *start << " "; start++;

}

}

int main()

{

int t1[] ={ 1, 7, 8, 4, 5 };

list l1(t1, t1 + 5);

int t2[] ={ 3, 2, 6, 9, 0 };

list l2(t2, t2 + 5);

l1.sort();

list::iterator it = l2.begin();

it++; it++;

l1.splice(l1.end(),l2, it, l2.end());

print(l1.begin(), l1.end()); cout<<"Size:"<

print(l2.begin(), l2.end()); cout<<"Size:"<

return 0;

}

What happens when you attempt to compile and run the following code?

#include

#include

#include

using namespace std;

int main ()

{

int t[] = {1, 2 ,3 ,4 ,5, 6 , 7, 8 , 9, 10};

vectorv1(t, t+10);

dequed1(t, t+10);

d1.empty();

v1.empty();

if (v1.isempty())

{

cout<<"I am empty ";

}

else

{

cout<<"I am not empty ";

}

cout<<v1.size()<<" "<

return 0;

}

What happens when you attempt to compile and run the following code?

#include

#include

class A {

public:

virtual int f() { return 10; }

virtual ~A(){}

};

class B: public A {

int f() {return 11; }

virtual ~B(){}

};

int main (){

std::vectorv1;

for(int i = 10; i>0; i??)

{

i%2>0?v1.push_back(new A()):v1.push_back(new B());

}

std::vector::iterator it = v1.begin();

while(it != v1.end())

{

std::cout<<v1.back()?>f()<<" ";

v1.pop_back();++it;

}

return 0;

}