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CPP Exam Dumps : C++ Certified Professional Programmer

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C++ Certified Professional Programmer Questions and Answers

Question 1

What happens when you attempt to compile and run the following code?

#include

#include

#include

#include

using namespace std;

templatestruct Out {

ostream & out;

Out(ostream & o): out(o){}

void operator() (const T & val ) { out<

int main() {

int t[]={3,2,4,1,5,6,10,8,7,9};

vector v1(t, t+10);

for_each(v1.begin(), v1.end(), bind1st(plus(), 1));

for_each(v1.rbegin(), v1.rend(), Out(cout));cout<<endl;

return 0;

}

Program outputs:

Options:

A.

3 2 4 1 5 6 10 8 7 9

B.

4 3 5 2 6 7 11 9 8 10

C.

9 7 8 10 6 5 1 4 2 3

D.

10 8 9 11 7 6 2 5 3 4

E.

compilation error

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Question 2

What happens when you attempt to compile and run the following code?

#include

#include

#include

using namespace std;

class B { int val;

public:

B(int v):val(v){}

int getV() const {return val;} bool operator < (const B & v) const { return val>v.val;} };

ostream & operator <<(ostream & out, const B & v) { out<

templatestruct Out {

ostream & out;

Out(ostream & o): out(o){}

void operator() (const T & val ) { out<

int main() {

B t1[]={3,2,4,1,5};

B t2[]={5,6,8,2,1};

vector v1(10,0);

sort(t1, t1+5);

sort(t2, t2+5);

set_intersection(t1,t1+5,t2,t2+5,v1.begin());

for_each(v1.begin(), v1.end(), Out(cout));cout<<endl;

return 0;

}

Program outputs:

Options:

A.

compilation error

B.

1 2 3 4 5 6 8 0 0 0

C.

1 2 3 4 5 6 8 2 1 0

D.

5 2 1 0 0 0 0 0 0 0

E.

1 2 5 0 0 0 0 0 0 0

Question 3

What will happen when you attempt to compile and run the following code?

#include

#include

#include

#include

#include

using namespace std;

int main() {

int t[] = { 3, 4, 2, 1, 0, 3, 4, 1, 2, 0 };

vector v(t, t + 10);

multimap m;

for (vector::iterator i = v.begin(); i != v.end(); i++) {

stringstream s;s << *i << *i;

m.insert(pair(*i, s.str()));

}

pair::iterator, multimap::iterator> range;

range = m.equal_range(2);

for (multimap::iterator i = range.first; i != range.second; i++) {

cout << i?>first << " ";

}

return 0;

}

The output will be:

Options:

A.

2 2

B.

1 2

C.

1 3

D.

2

E.

0 2