CPP Exam Dumps : C++ Certified Professional Programmer

What happens when you attempt to compile and run the following code?

#include

#include

#include

#include

using namespace std;

templatestruct Out {

ostream & out;

Out(ostream & o): out(o){}

void operator() (const T & val ) { out<

int main() {

int t1[]={3,2,4,1,5};

int t2[]={6,10,8,7,9};

vector v1(5);

transform(t1,t1+5,t2,v1.rbegin(), plus());

for_each(v1.rbegin(), v1.rend(), Out(cout));cout<<endl;

return 0;

}

Program outputs:

What happens when you attempt to compile and run the following code?

#include

#include

#include

#include

#include

using namespace std;

struct display {

void operator() (int i) {cout << " " << i;}

};

int main() {

int t[] = { 10, 5, 9, 6, 2, 4, 7, 8, 3, 1 };

vector v1(t, t + 10);

deque d1(t, t + 10);

set s1(t, t + 10);

for_each(v1.begin(), v1.end(), display); //Line I

for_each(d1.begin(), d1.end(), *(new display())); // Line II

for_each(s1.begin(), s1.end(), display()); // Line III

return 0;

}

What will happen when you attempt to compile and run the following code?

#include

#include

#include

#include

#include

using namespace std;

int main() {

int t[] = { 3, 4, 2, 1, 0, 3, 4, 1, 2, 0 };

vector v(t, t + 10);

multimap m;

for (vector::iterator i = v.begin(); i != v.end(); i++) {

stringstream s;s << *i << *i;

m.insert(pair(*i, s.str()));

}

pair::iterator, multimap::iterator> range;

range = m.equal_range(2);

for (multimap::iterator i = range.first; i != range.second; i++) {

cout << i?>first << " ";

}

return 0;

}

The output will be: