C++ Institute Related Exams
CPP Exam
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out< int main() { int t1[]={3,2,4,1,5}; int t2[]={6,10,8,7,9}; vector sort(t1, t1+5); sort(t2, t2+5); copy(t1,t1+5,v1.begin()); copy(t2,t2+5,v1.begin()+5); merge(v1.begin(), v1.begin()+5,v1.end()); for_each(v1.begin(), v1.end(), Out return 0; } Program outputs:
What will happen when you attempt to compile and run the following code? Choose all possible answers.
#include
using namespace std;
class B {};
template
class A {
T_v;
public:
A() {}
A(T v): _v(v){}
T getV() { return _v; }
void add(T a) { _v+=a; }
};
int main()
{
A
Ab;
a.add(10);
cout << a.getV() < return 0; }
What happens when you attempt to compile and run the following code?
#include
#include
class A {
public:
virtual int f() { return 10; }
virtual ~A(){}
};
class B: public A {
int f() {return 11; }
virtual ~B(){}
};
int main (){
std::vectorv1;
for(int i = 10; i>0; i??)
{
i%2>0?v1.push_back(new A()):v1.push_back(new B());
}
std::vector::iterator it = v1.begin();
while(it != v1.end())
{
std::cout<<v1.back()?>f()<<" ";
v1.pop_back();++it;
}
return 0;
}