C++ Institute Related Exams
CPP Exam
What happens when you attempt to compile and run the following code?
#include
#include
using namespace std;
int main() {
int t[] = { 1, 1, 2, 2, 3, 3, 4, 4, 5, 5 };
string s[] = { "one", "one", "two", "two", "three","three", "four", "four", "five", "five"};
map
for (int i = 0; i < 10; i++) {
m.push_back(pair
}
for (map
cout << i?>first << " ";
}
return 0;
}
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
using namespace std;
class B { int val;
public:
B(int v=0):val(v){}
int getV() const {return val;}
operator int () const { return val;} };
ostream & operator <<(ostream & out, const B & v) { out< template ostream & out; Out(ostream & o): out(o){} void operator() (const T & val ) { out< int main() { B t[]={3,2,4,1,5,6,10,8,7,9}; vector v1(t, t+10); transform(v1.begin(), v1.end(), v1.begin(), bind2nd(plus(), 1)); for_each(v1.rbegin(), v1.rend(), Out(cout));cout<<endl; return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
class A {
public:
virtual int f() { return 10; }
virtual ~A(){}
};
class B: public A {
int f() {return 11; }
virtual ~B(){}
};
int main (){
std::vectorv1;
for(int i = 10; i>0; i??)
{
i%2>0?v1.push_back(new A()):v1.push_back(new B());
}
std::vector::iterator it = v1.begin();
while(it != v1.end())
{
std::cout<<v1.back()?>f()<<" ";
v1.pop_back();++it;
}
return 0;
}