C++ Institute Related Exams
CPP Exam
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
#include
using namespace std;
struct display {
void operator() (int i) {cout << " " << i;}
};
int main() {
int t[] = { 10, 5, 9, 6, 2, 4, 7, 8, 3, 1 };
vector
deque
set
for_each(v1.begin(), v1.end(), display); //Line I
for_each(d1.begin(), d1.end(), *(new display())); // Line II
for_each(s1.begin(), s1.end(), display()); // Line III
return 0;
}
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
template
int calculate(T start, T end)
{
int s = 0;
while (start != end)
s+= *start; start++;return s;
}
int main ()
{
int t[] = {1, 2 ,3 ,4 ,5, 6 , 7, 8 , 9, 10};
vector
deque
cout<<calculate(t,t+10)<<" ";
cout<<calculate(v1.begin()+1,v1.end()?2)<<" ";
cout<<calculate(d1.rbegin()+1,d1.rend()?2)<<" ";
cout<<calculate(t[0],t[10])<<" ";
cout<<endl;
return 0;
}
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out< int main() { int t1[]={3,2,4,1,5}; int t2[]={6,10,8,7,9}; vector sort(t1, t1+5); sort(t2, t2+5); copy(t1,t1+5,v1.begin()); copy(t2,t2+5,v1.begin()+5); merge(v1.begin(), v1.begin()+5,v1.end()); for_each(v1.begin(), v1.end(), Out return 0; } Program outputs: