All CTAL-TTA Test Inside ISTQB Questions

Once existing test cases have been identified for refactoring, the next step is typically to make changes to the internal structure of these tests to improve their maintainability. This involves revising the code or scripts to make them cleaner, more efficient, and easier to understand, which helps in maintaining them over time as the software evolves. This process may also involve updating test data or dependencies to ensure that the tests remain robust and reliable .

The key context here is the challenge of managing limited resources, particularly ROM and RAM, due to severe restrictions on code size in consumer electronics. Lazy instantiation is a design pattern that defers the creation of an object until the first time it is needed. This approach can significantly reduce the application's memory footprint by avoiding unnecessary pre-allocation of memory, which is particularly valuable in systems where memory resources are constrained. In reviewing the architecture for such a system, it's crucial to ensure that objects are only created when necessary and that memory is optimally managed. Hence, the focus on lazy instantiation would be most important to ensure that the system uses resources efficiently and remains within the restricted code size.

API testing tends to focus on individual inputs more than combinations of inputs. This is because APIs, as the intermediary layers of software, often handle specific types of data input and output rather than user interaction sequences. GUI testing, on the other hand, involves testing the interface with which the user interacts, which frequently includes testing various combinations of user inputs and sequences to simulate actual user scenarios. Thus, GUI testing typically requires checking the integration and behavior of elements in combination to ensure they work together as expected in a user environment .

To achieve 100% decision coverage, we need to ensure that every decision (if statement) in the code has been tested for both true and false outcomes. Let's analyze the code and count the decisions:

IF (Room_price > 200)

IF (Loyalty_level = Platinum) inside Room_price > 200

ELSE within the same decision above

IF (Loyalty_level = Gold) inside the ELSE of decision 2

IF (Room_price > 150)

IF (Loyalty_level = Platinum) inside Room_price > 150

ELSE within the same decision above

IF (Discount_factor < 100%)

To cover all these decisions, we need test cases for each possible combination:

Room_price > 200 and Loyalty_level = Platinum.

Room_price > 200 and Loyalty_level = Gold.

Room_price > 200 and Loyalty_level not Platinum or Gold.

Room_price <= 200 and Room_price > 150, and Loyalty_level = Platinum.

Room_price <= 200 and Room_price > 150, and Loyalty_level not Platinum.

Room_price <= 150.

From these scenarios, we can see that the minimum number of test cases required to achieve 100% decision coverage is four:

Test with Room_price > 200 and Loyalty_level = Platinum (tests decision 1 true, 2 true, and 8 true).

Test with Room_price > 200 and Loyalty_level = Gold (tests decision 1 true, 2 false, 4 true, and 8 true).

Test with Room_price > 200 and Loyalty_level not Platinum or Gold (tests decision 1 true, 2 false, 4 false, and 8 true).

Test with Room_price <= 200 and Room_price > 150, and Loyalty_level = Platinum (tests decision 1 false, 5 true, 6 true, and 8 true).

Test with Room_price <= 200 and Room_price > 150, and Loyalty_level not Platinum (tests decision 1 false, 5 true, 6 false, and 8 true).

Test with Room_price <= 150 (tests decision 1 false, 5 false, and 8 false).

Given that these six cases test all branches, four test cases are required to ensure that all decisions are covered at least once.

Therefore, the correct answer is A. 4.