The two code fragments that compile are B and E. These are the only ones that use the correct syntax for declaring and initializing a var variable. The var keyword is a reserved type name that allows the compiler to infer the type of the variable based on the initializer expression. However, the var variable must have an initializer, and the initializer must not be null or a lambda expression. Therefore, option A is invalid because it does not have an initializer, option C is invalid because it has a null initializer, and option D is invalid because it has a lambda expression as an initializer. Option B is valid because it has a String initializer, and option E is valid because it has an int initializer.
Question 3
Given the code fragment:
Which action enables the code to compile?
Options:
A.
Replace record with void.
B.
Remove the regNO initialization statement.
C.
Make the regNo variable static.
D.
Replace thye regNo variable static
E.
Make the regNo variable public
Answer:
E
Explanation:
Explanation:
The code will compile if the regNo variable is made public. This is because the regNo variable is being accessed in the main method of the App class, which is outside the scope of the Product class. Making the regNo variable public will allow it to be accessed from outside the class. References: