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Snowflake DEA-C01 Exam With Confidence Using Practice Dumps

Exam Code:
DEA-C01
Exam Name:
SnowPro Advanced: Data Engineer Certification Exam
Certification:
Vendor:
Questions:
65
Last Updated:
Jan 24, 2025
Exam Status:
Stable
Snowflake DEA-C01

DEA-C01: Snowflake Certification Exam 2024 Study Guide Pdf and Test Engine

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SnowPro Advanced: Data Engineer Certification Exam Questions and Answers

Question 1

A company has an extensive script in Scala that transforms data by leveraging DataFrames. A Data engineer needs to move these transformations to Snowpark.

…characteristics of data transformations in Snowpark should be considered to meet this requirement? (Select TWO)

Options:

A.

It is possible to join multiple tables using DataFrames.

B.

Snowpark operations are executed lazily on the server.

C.

User-Defined Functions (UDFs) are not pushed down to Snowflake

D.

Snowpark requires a separate cluster outside of Snowflake for computations

E.

Columns in different DataFrames with the same name should be referred to with squared brackets

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Question 2

A Data Engineer has written a stored procedure that will run with caller's rights. The Engineer has granted ROLEA right to use this stored procedure.

What is a characteristic of the stored procedure being called using ROLEA?

Options:

A.

The stored procedure must run with caller's rights it cannot be converted later to run with owner's rights

B.

If the stored procedure accesses an object that ROLEA does not have access to the stored procedure will fail

C.

The stored procedure will run in the context (database and schema) where the owner created the stored procedure

D.

ROLEA will not be able to see the source code for the stored procedure even though the role has usage privileges on the stored procedure

Question 3

How can the following relational data be transformed into semi-structured data using the LEAST amount of operational overhead?

Options:

A.

Use the to_json function

B.

Use the PAESE_JSON function to produce a variant value

C.

Use the OBJECT_CONSTRUCT function to return a Snowflake object

D.

Use the TO_VARIANT function to convert each of the relational columns to VARIANT.