Passed Exam Today 1z0-071

For the question about the INTERSECT operator in SQL:

A. It processes NULLS in the selected columns: The INTERSECT operator compares two SELECT statements and returns rows that exist in both queries. It considers NULLs during this process, and NULLs in corresponding columns must match for rows to be considered equal. This means if both selected columns in the intersecting queries have NULLs, those rows will be included in the output.

Incorrect options:

B: INTERSECT has higher precedence than UNION and UNION ALL, not lower.

C: It does not ignore NULLs; rather, it processes them, as explained.

D: Multiple INTERSECT operators are indeed possible in the same SQL statement, allowing for complex compound queries.

For SQL queries involving set operations like UNION, UNION ALL, INTERSECT, and MINUS, the data types and number of columns in the SELECT statements being combined must be the same. Here is a breakdown of each query option:

Option A: This query successfully combines results from two tables using UNION ALL, which combines all rows from both SELECT statements, including duplicates. Both queries select two columns (prod_id and exp_date, with exp_date being NULL in the second query). This is valid as the number of columns and their data types match.

Option B: This query attempts to use INTERSECT, which returns only the rows common to both SELECT statements. However, the first SELECT statement chooses prod_id and prod_name, while the second only substitutes a constant value for prod_id without specifying from which table it selects prod_name. If "newproducts" (presumably a typo and should be "new_products") does not have the exact columns as "products", or if the data types do not match, it will fail.

Option C: This query uses UNION, which removes duplicates from the combined dataset. The use of SELECT * assumes that both "products" and "new_products" tables have the same columns in the same order with matching data types. This query will succeed if those conditions are met.

Option D: This query uses MINUS to subtract results of the second SELECT from the first. However, it fails because 'k' does not explicitly match a column name in "products", suggesting a potential error unless 'k' is indeed a valid column.

Option E: This query fails because the first SELECT statement fetches only one column (prod_id) while the second fetches two columns (prod_id and prod_name). UNION ALL requires the same number of columns with compatible types in all SELECT statements involved.

A. False. Constraints are enforced during INSERT and UPDATE operations, and by the nature of their definition, they impact DELETE operations as well (in the case of referential constraints).

B. False. A column with a foreign key constraint can contain a NULL value unless it is also constrained to be NOT NULL.

C. False. Not all constraints can be defined at the column level. For example, some constraints such as FOREIGN KEY constraints are more commonly defined at the table level.

D. True. A constraint can be disabled regardless of whether the constrained column contains data. However, re-enabling the constraint requires that all data satisfy the constraint rules.

E. True. A column with a UNIQUE constraint can indeed contain a NULL value, as NULL is considered not equal to any value, including itself. This means that multiple rows with NULL values do not violate the UNIQUE constraint.

References:

Oracle Documentation on Constraints:

Oracle Documentation on Enabling and Disabling Constraints:

In SQL, to return all rows from one table in a join regardless of whether they match rows in the other table, a LEFT JOIN is used when we want all rows from the left table, or a RIGHT JOIN when we want all rows from the right table. Here’s an explanation for each query provided in the context of the COLORS and BRICKS tables:

A. This query uses a LEFT JOIN and will return all the rows from the COLORS table (c) because it is on the left side of the join. Additionally, it joins the BRICKS table (b) on the condition that the color_rgb_hex_value matches. The condition in the WHERE clause (b.brick_id > 0) will not exclude any COLORS rows because it only filters the rows from the right table (BRICKS) after the join.

B. This query uses a RIGHT JOIN, and while it does return all rows from the COLORS table, it doesn't place it on the left side of the join, which is not what is typically expected from a RIGHT JOIN to return all rows from the right side table.

C. This query is a plain JOIN (also known as an inner join), which only returns rows that have matching values in both tables, so it will not return all the rows from the COLORS table if there is no match in the BRICKS table.

D. This query uses a FULL JOIN, which returns all rows when there is a match in one of the tables. Hence, it will return all the rows from both the COLORS and BRICKS tables. While this does return all rows from the COLORS table, it also includes all rows from the BRICKS table, which may not be desired if the requirement was only to return all rows from COLORS.

E. This query is similar to option A and uses the USING clause to specify the join condition. The USING clause is used when both tables have a column with the same name and is meant to simplify the syntax. However, in this case, the columns do not have the same name in both tables (RGB_HEX_VALUE in COLORS and COLOR_RGB_HEX_VALUE in BRICKS), so this query will not execute successfully.

References:

Oracle Database SQL Language Reference, 12c Release 1 (12.1): "Joins"

Oracle Database SQL Language Reference, 12c Release 1 (12.1): "LEFT OUTER JOIN"

Oracle Database SQL Language Reference, 12c Release 1 (12.1): "RIGHT OUTER JOIN"

Oracle Database SQL Language Reference, 12c Release 1 (12.1): "FULL OUTER JOIN"

Based on the explanations above, the correct answers that return all rows from the COLORS table are A and D. However, D includes all rows from BRICKS as well, which may not be the intended requirement if the question specifies only rows from COLORS should be returned. Thus, A is the most accurate answer to the question as it adheres to the standard expectation of a LEFT JOIN.