Newly Released ASQ CSSBB Exam PDF

The correct answer is D. implementing corrective action on items that have high risk priority number or severity values . The CSSBB source explains that after assigning probability (P) , severity (S) , and detection (D) , the risk priority number (RPN) is calculated as RPN = P × S × D . It further states that actions are then based on items that either have the highest RPN or have major safety issues .

This means the team should not rely on an arbitrary cutoff like RPN > 100. The source also emphasizes severity separately, especially for safety-related consequences and nonconformance risk. Therefore, the practical FMEA focus is to take action on the items with the highest combined risk and on any items with very high severity, even if the total RPN is not the absolute highest. The other choices are incorrect because alpha risk is unrelated to FMEA, and creating flowcharts is not the main prioritization rule. Thus, the verified CSSBB answer is D .

The correct answer is B. Paired t test . The key phrase in the question is that the team measures the same hard drives before and after repair. In CSSBB statistics, a paired t test is used when data are taken in pairs , with a difference calculated for each pair. The CSSBB source states that the paired t test “tests the difference between 2 sample means” when the “data is taken in pairs,” and that a different d is calculated for each pair.

This is exactly a before-versus-after situation on the same units, so the observations are dependent , not independent. The supplemental material also explains paired sampling as pre-test/post-test measurements on the same element , which confirms that this is not an ordinary two-sample independent t test. ANOVA is used for comparing three or more means, and the F test is used to compare variances. Therefore, the proper CSSBB-aligned test for performance differences on each drive is the paired t test .

The correct answer is B. capture knowledge to use in other areas . In the CSSBB control-phase material, lessons learned are part of the sustain-improvements process and include identifying what the team did well, what should be done differently in the future, and whether other processes or applications should be reviewed for similar improvements. The results are retained with project documentation and archived for future reference.

The supplemental Lean Six Sigma material states this even more directly: the documentation plan is necessary so that what has been learned from the project is captured, shared, and institutionalized , becoming part of the organization’s knowledge base. It specifically includes purposes such as sharing information , managing best practices , and applying lessons learned to new projects . This shows that lessons learned are intended to transfer knowledge beyond the original team and project. They are not primarily for SPC implementation, singling out resistant employees, or identifying teams for rewards. Therefore, the best verified answer is B , because lessons learned help preserve and reuse organizational knowledge in other projects and areas.

The correct answer is B. Reduce defects . The CSSBB source defines rolled throughput yield (RTY) as the cumulative yield through multiple process steps and gives the formula as the product of the yields for each step . It also notes that RTY is the probability that a unit successfully completes all process requirements across all steps. The supplemental Lean Six Sigma material states explicitly that RTY decreases due to defects, even if the defects are corrected .

Because RTY is driven directly by first-pass success at each step, the most effective way to increase RTY is to reduce defects and improve first-time yield in the process steps that are causing losses. Reducing inventory, developing productivity metrics, or using 5S may support improvement efforts indirectly, but none of those changes RTY as directly as lowering defect opportunities and rework. The CSSBB example also shows that low-yield steps point to where improvement projects should focus. Therefore, the best verified answer is B. Reduce defects .