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UEFI firmware is a software program that provides the interface between the hardware and the operating system on a computer. UEFI stands for Unified Extensible Firmware Interface and it is a replacement for the traditional BIOS (Basic Input/Output System). UEFI firmware has several advantages over BIOS, such asfaster boot times, better security, larger disk support, and graphical user interface. Some of the features of UEFI firmware are12:

• It can use and read certain file systems: UEFI firmware can access files on partitions formatted with FAT12, FAT16, or FAT32 file systems. This allows UEFI to load boot loaders, kernels, and configuration files from these partitions without relying on the legacy MBR (Master Boot Record) or boot sector code. UEFI firmware can also support other file systems, such as NTFS or ext4, with additional drivers.
• It is loaded from a fixed boot disk position: UEFI firmware is stored in a ROM chip on the motherboard, but it also requires a special partition on the boot disk to store additional files and drivers. This partition is called the EFI System Partition (ESP) and it is usually the first partition on the disk. The ESP must have a specific GUID (Globally Unique Identifier) and must be formatted with a FAT file system. The UEFI firmware will look for the ESP on the boot disk and load the files from there.

The other options are false or irrelevant. UEFI firmware does not read and interpret partition tables, it relies on the operating system to do that. UEFI firmware does not store its entire configuration on the /boot/ partition, it stores some of its settings in the NVRAM (Non-Volatile Random Access Memory) on the motherboard and some of its files on the ESP. UEFI firmware is not stored in a special area within the GPT (GUID Partition Table) metadata, it is stored in a ROM chip and an ESP. GPT is a partitioning scheme that supports larger disks and more partitions than the legacy MBR scheme. References:

• Linux Essentials - Linux Professional Institute Certification Programs1
• Exam 101 Objectives - Linux Professional Institute2
• How to Boot and Install Linux on a UEFI PC With Secure Boot3
• How to Access UEFI Settings From Linux - It’s FOSS4
• UEFI firmware updates for linux-surface - GitHub5

The correct answer is C, s/txt$/bak.txt/. This regular expression will turn the input stream into the desired output stream by using the s command, which is used to substitute or replace a pattern with another pattern. The syntax of the s command is:

s/pattern/replacement/

The pattern is the regular expression that matches the text to be replaced, and the replacement is the text that replaces the matched text. The / symbol is used as a delimiter to separate the pattern and the replacement, but other characters can be used as well.

The pattern in this regular expression is txt$, which means that it will match the string txt at the end of the line. The $ symbol is an anchor that matches the end of the line. The replacement in this regular expression is bak.txt, which means that it will replace the matched string with the string bak.txt.

Therefore, the command s/txt$/bak.txt/ will replace the string txt at the end of each line with the string bak.txt, resulting in the following output stream:

txt1.bak.txt atxt.bak.txt txtB.bak.txt

The other regular expressions are incorrect for the following reasons:

• A, s/^.txt/.bak/: This regular expression will not work as expected, because it has several errors. First, the pattern in this regular expression is ^.txt, which means that it will match the string .txt at the beginning of the line. The ^ symbol is an anchor that matches the beginning of the line. However, none of the lines in the input stream start with .txt, so the pattern will not match anything. Second,the replacement in this regular expression is .bak, which means that it will replace the matched string with the string .bak. However, this will not produce the desired output, because it will not append the string .txt to the end of the line, but rather replace the existing string with .bak.
• B, s/txt/bak.txt/: This regular expression will not work as expected, because it has several errors. First, the pattern in this regular expression is txt, which means that it will match the string txt anywhere in the line, not just at the end. This will cause unwanted replacements in the middle of the words, such as atxt and txtB. Second, the replacement in this regular expression is bak.txt, which means that it will replace the matched string with the string bak.txt. However, this will not produce the desired output, because it will not preserve the original string, but rather replace it with bak.txt.
• D, s/txt$/.bak/: This regular expression will not work as expected, because it has several errors. First, the pattern in this regular expression is ^txt$, which means that it will match the string txt only if it is the entire line. The ^ and $ symbols are anchors that match the beginning and the end of the line, respectively. However, none of the lines in the input stream are exactly txt, so the pattern will not match anything. Second, the replacement in this regular expression is .bak^, which means that it will replace the matched string with the string .bak^. However, this will not produce the desired output, because it will not append the string .txt to the end of the line, but rather replace the existing string with .bak^, which is not a valid file name.
• E, s/[.txt]/.bak$1/: This regular expression will not work as expected, because it has several errors. First, the pattern in this regular expression is [.txt], which means that it will match any one of the characters inside the brackets, which are ., t, and x. This will cause unwanted replacements of single characters, such as the dot in the file extension or the letter t in the word atxt. Second, the replacement in this regular expression is .bak$1, which means that it will replace the matched character with the string .bak followed by the first backreference. A backreference is a way to refer to a part of the pattern that was captured by parentheses. However, there are no parentheses in the pattern, so the backreference $1 is invalid and will not work. Third, the replacement in this regular expression will not produce the desired output, because it will not append the string .txt to the end of the line, but rather replace the existing character with .bak$1, which is not a valid file name.

References:

• How to Use Regular Expressions (regexes) on Linux - How-To Geek
• How to Use Regular Expressions (RegEx) on Linux - GeeksforGeeks
• A beginner’s guide to regular expressions with grep - Red Hat Developer
• [Regular Expressions - Linux Documentation Project]
• [Regular Expressions in Linux Explained with Examples - Linux Handbook].

[character list] matches any one of the characters in the list. ? matches any single character. * matches any number of characters, including none.

Therefore, the wildcard ttyS[1-5] will match any filename that starts with ttyS and ends with a digit from 1 to 5, such as ttyS1, ttyS2, ttyS3, ttyS4, or ttyS5. However, it will not match ttyS0, which has a 0 at the end.

The wildcard tty?[0-5] will match any filename that starts with tty, followed by any single character, followed by a digit from 0 to 5, such as ttyS0, ttyS1, ttyS2, ttyA0, ttyB5, or ttyZ4. This wildcard will match all the given filenames.

The wildcard tty*2 will match any filename that starts with tty and ends with 2, such as ttyS2, ttyA2, ttyB2, or ttyZZZ2. This wildcard will match ttyS2, but not the other two filenames.

The wildcard tty[A-Z][012] will match any filename that starts with tty, followed by a capital letter from A to Z, followed by a digit from 0 to 2, such as ttyA0, ttyB1, ttyC2, ttyZ0, or ttyZ2. This wildcard will match ttyS0 and ttyS2, but not ttyS1, which has a 1 at the end.

The wildcard tty[Ss][02] will match any filename that starts with tty, followed by either S or s, followed by either 0 or 2, such as ttyS0, ttyS2, ttys0, or ttys2. This wildcard will match ttyS0 and ttyS2, but not ttyS1, which has a 1 at the end.

The correct answer is A, tr -d ‘\r’ < userlist.txt > newlist.txt. This command will use the tr utility to delete the carriage return characters (\r) from the userlist.txt file and redirect the output to the newlist.txt file. The tr utility is used to translate, delete, or squeeze characters from the standard input and write the result to the standard output. The syntax of the tr command is:

tr [options] set1 [set2]

The options can modify the behavior of the tr command, such as complementing, squeezing, or truncating the sets of characters. The set1 and set2 are strings of characters that specify the translation to be performed. The characters in set1 are replaced by the corresponding characters in set2. If set2 is omitted, the characters in set1 are deleted.

The -d option tells tr to delete the characters in set1 from the output. The \r character is a special escape sequence that represents the carriage return character, which is used in Windows systems to mark the end of a line, along with the line feed character (\n). The < and > symbols are redirection operators that redirect the input and output of a command to a file or device. The < symbol redirects the standard input of a command from a file, while the > symbol redirects the standard output of a command to a file, overwriting any existing content.

Therefore, the command tr -d ‘\r’ < userlist.txt > newlist.txt will read each character from the userlist.txt file, delete any carriage return characters, and write the output to the newlist.txt file. This will effectively change all CR-LF line breaks (\r\n) in the userlist.txt file to Linux standard LF line breaks (\n) and store the result in newlist.txt.

The other commands are incorrect for the following reasons:

• B, tr -c ‘\n\r’ ‘’ userlist.txt: This command will not work as expected, because it has several errors. First, the -c option tells tr to complement the set of characters in set1, which means that the operations will apply to the characters that are not in the set1. However, the set1 in this command is ‘\n\r’, which includes both the line feed and the carriage return characters, so the complement will be all the other characters except these two. Second, the set2 in this command is an empty string (‘’), which means that tr will delete the characters that match the set1 (or its complement, in this case). Third, the redirection operators are reversed, which means that tr will read the input from the newlist.txt file and write the output to the userlist.txt file, instead of the other way around. Therefore, the command tr -c ‘\n\r’ ‘’ userlist.txt will delete all the characters except the line feed and the carriage return characters from the newlist.txt file and overwrite the userlist.txt file with the output, which will be a series of blank lines.
• C, tr ‘\r\n’ ‘’ newlist.txt: This command will not work as expected, because it has several errors. First, the set1 in this command is ‘\r\n’, which means that tr will match the carriage return and the line feed characters separately, not as a pair. Second, the set2 in this command is an empty string (‘’), which means that tr will delete the characters that match the set1. Third, the redirection operators are missing, which means that tr will not read the input from the userlist.txt file or write the output to the newlist.txt file, but instead it will expect the input from the standard input and write the output to the standard output. Therefore, the command tr ‘\r\n’ ‘’ newlist.txt will delete all the carriage return and the line feed characters from the standard input and write the output to the standard output, and treat the userlist.txt and newlist.txt as additional arguments that will cause an error.
• D, tr ‘\r’ ‘\n’ userlist.txt newlist.txt: This command will not work as expected, because it has several errors. First, the set1 and set2 in this command are ‘\r’ and ‘\n’, which means that tr will replace the carriage return characters with the line feed characters, not delete them. Second, the redirection operators are missing, which means that tr will not read the input from the userlist.txt file or write the output to the newlist.txt file, but instead it will expect the input from the standard input and write the output to the standard output. Third, the userlist.txt and newlist.txt are treated as additional arguments that will cause an error. Therefore, the command tr ‘\r’ ‘\n’ userlist.txt newlist.txt will replace all the carriage return characters with the line feed characters from the standard input and write the output to the standard output, and report an error for the extra arguments.
• E, tr -s ‘/M/J/’ userlist.txt newlist.txt: This command will not work as expected, because it has several errors. First, the -s option tells tr to squeeze the repeated characters in set1 with a single occurrence, not delete them. Second, the set1 in this command is ‘/M/J/’, which is not a valid escape sequence for the carriage return and the line feed characters. The correct escape sequences are ‘\r’ and ‘\n’, respectively. Third, the redirection operators are missing, which means that tr will not read the input from the userlist.txt file or write the output to the newlist.txt file, but instead it will expect the input from the standard input and write the output to the standard output. Fourth, the userlist.txt and newlist.txt are treated as additional arguments that will cause an error. Therefore, the command tr -s ‘/M/J/’ userlist.txt newlist.txt will squeeze the repeated occurrences of the characters /, ^, M, and J from the standard input and write the output to the standard output, and report an error for the extra arguments.

References:

• Tr Command in Linux with Examples | Linuxize
• tr command in Unix/Linux with examples - GeeksforGeeks
• How to Use the Linux tr Command - How-To Geek
• [tr(1) - Linux manual page - man7.org]
• [Linux tr command help and examples - Computer Hope].