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1D0-541 Exam Results

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Total 128 questions
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CIW v5 Database Design Specialist Questions and Answers

Question 13

Which characteristic is an advantage of a database management system?

Options:

A.

Data files are owned and maintained by the users.

B.

Database administration is simplified.

C.

A standard method can be used to access the database.

D.

Data is decentralized.

Question 14

Consider the Information Engineering diagram shown in the exhibit for a building management company. Referential integrity must be maintained such that a building cannot be deleted when it has residents. Building_ID, R_ID, Room_Count and Room_Num are integer numbers, whereas Bldg_Name, Location and Res_Name are all represented by variable-length strings with a maximum of 20 characters. Which SQL statement best implements the relations shown in this diagram?

Options:

A.

CREATE TABLE BUILDING (

Building_ID INTEGER NOT NULL PRIMARY KEY,

Bldg_Name VARCHAR (20),

Location VARCHAR (20),

Room_Count INTEGER );

CREATE TABLE RESIDENT (

R_ID NOT NULL PRIMARY KEY,

Room_Num INTEGER,

Res_Name VARCHAR (20),

Building_ID INTEGER NOT NULL,

FOREIGN KEY Building_ID REFERENCES RESIDENT (Building_ID)

ON DELETE NO CHECK);

B.

CREATE TABLE BUILDING (

Building_ID INTEGER NOT NULL PRIMARY KEY,

Bldg_Name VARCHAR (20),

Location VARCHAR (20),

Room_Count INTEGER );

CREATE TABLE RESIDENT (

R_ID NOT NULL PRIMARY KEY,

Room_Num INTEGER,

Res_Name VARCHAR (20),

Building_ID INTEGER NOT NULL,

FOREIGN KEY Building_ID REFERENCES BUILDING (Building_ID)

ON DELETE NO CHECK

ON UPDATE CASCADE);

C.

CREATE TABLE BUILDING (

Building_ID INTEGER NOT NULL PRIMARY KEY,

Bldg_Name VARCHAR (20),

Location VARCHAR (20),

Room_Count INTEGER );

CREATE TABLE RESIDENT (

R_ID NOT NULL PRIMARY KEY,

Room_Num INTEGER,

Res_Name VARCHAR (20),

Building_ID INTEGER NOT NULL,

FOREIGN KEY Building_ID REFERENCES BUILDING (Building_ID)

ON DELETE NO CHECK

ON UPDATE CASCADE);

D.

CREATE TABLE BUILDING (

Building_ID INTEGER NOT NULL PRIMARY KEY,

Bldg_Name VARCHAR (20),

Location VARCHAR (20),

Room_Count INTEGER );

CREATE TABLE RESIDENT (

R_ID NOT NULL PRIMARY KEY,

Room_Num INTEGER,

Res_Name VARCHAR (20),

Building_ID INTEGER NOT NULL,

FOREIGN KEY Building_ID REFERENCES BUILDING (Building_ID)

ON DELETE NO CHECK

ON UPDATE CASCADE);

Question 15

Consider the relations shown in the exhibit. Which of the following SQL statements would enter data from the Customers relation into the Atlanta_Customers relation?

Options:

A.

INSERT INTO Atlanta_Customers

VALUES( SELECT * FROM

Customer s WHERE Sales_Office =

Atlanta

B.

INSERT INTO Atlanta_Customers

SELECT * FROM Customers

WHERE Sales_Office = Atlanta

C.

INSERT INTO Atlanta_Customers SELECTCust_No,

Cust_Name, Satisfaction_Rate, Sales_Rep_No FROM Customers

WHERE Sales_Office = Atlanta

D.

INSERT INTO Atlanta_Customers SELECT Cust_No,

Cust_Name, Sales_Office, Sales_Rep_No FROM Customers

WHERE Sales_Office = Atlanta

Question 16

Consider the Employee relation shown in the exhibit. A database manager wants to set up a view called Emp_Dept that allows users to find employees and their department ID numbers. Which SQL statement will accomplish this?

Options:

A.

CREATE VIEW Emp_Dept AS SELECT

Last_Name, First_Name, Dept_ID FROM

Employee;

B.

UPDATE VIEW Emp_Dept

AS SELECT * FROM

Employee;

C.

UPDATE VIEW Emp_Dept AS SELECT

Last_Name, First_Name, Dept_ID FROM

Employee;

D.

CREATE VIEW Emp_Dept

AS SELECT * FROM

Employee WHERE ID = 0001

AND ID = 0002 AND ID =

0003 AND ID = 0004;

Page: 4 / 5
Total 128 questions
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